Respuesta :

konrad509

[tex] |\Omega|=AK=10\\
|A|=FG=6-5=1\\\\
P(A)=\dfrac{1}{10}\Rightarrow \text{a} [/tex]

Answer: 1/10


Step-by-step explanation:

Each space is equal to 1/10. AK = 10. So if we try to find the probability of landing in FG, that's only one space. Therefore it would only be 1/10. If we were trying to land in CG it would be 4/10. Does that make sense?

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