Respuesta :

gmany

[tex]Area=\dfrac{25}{36}\ yd^2\\\\Area=s\cdot s=s^2\\\Downarrow\\s^2=\dfrac{25}{36}\to s=\sqrt{\dfrac{25}{36}}\\\\s=\dfrac{\sqrt{25}}{\sqrt{36}}\\\\\boxed{s=\dfrac{5}{6}\ yd}[/tex]

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