Answer: The vertex is (7,36)
Explanation:
We are looking for the vertex point (xv,yv) of the parabola. Use the formula for the vertex coordinate xv first, then use that value to oobtain yv:
[tex]y=ax^2+bx+c\\y=x^2-14x+13\\\implies a=1, b=-14\\x_v=\frac{-b}{2a}=\frac{14}{2}=7\\y_v=7^2-14\cdot7+13=49-98+13=36[/tex]
