Answer:
Step-by-step explanation:
[tex]\dfrac{1}{3}y+1\leq4\qquad\text{subtract 1 from both sides}\\\\\dfrac{1}{3}y\leq3\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}y\leq(3)(3)\\\\y\leq9[/tex]
