Answer:
Step-by-step explanation:
[tex]-\dfrac{1}{5}x<-3\qquad\text{change the signs}\\\\\dfrac{1}{5}x>3\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{1}{5\!\!\!\!\diagup_1}x<(5)(-3)\\\\x<-15[/tex]
