Answer:
Step-by-step explanation:
[tex]\dfrac{-1}{3}b\geq5\qquad\text{change the signs}\\\\\dfrac{1}{3}b\leq-5\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}b\leq(3)(-5)\\\\b\leq-15[/tex]
