[tex]y=\dfrac{1}{2}x+2\\\\for\ x=0\to y=\dfrac{1}{2}(0)+2=0+2=2\to(0;\ 2)\\\\for\ x=2\to y=\dfrac{1}{2}(2)+2=1+2=3\to(2;\ 3)\\\\y=2x-1\\\\for\ x=0\to y=2(0)-1=0-1=-1\to(0;\ -1)\\\\for\ x=2\to y=2(2)-1=4-1=3\to(2;\ 3)\\\\Look\ at\ the\ picture.\\\\Answer:\ (2;\ 3)\to x=2;\ y=3.[/tex]
