Answer: [tex]\boxed{\dfrac{2}{5}}[/tex]
f(3)
Put the value of x = 3 to the equation of the function
[tex]f(x)=\dfrac{4}{5}x-2\\\\f(3)=\dfrac{4}{5}\cdot3-2=\dfrac{4\cdot3}{5}-2=\dfrac{12}{5}-\dfrac{10}{5}=\dfrac{12-10}{5}=\boxed{\dfrac{2}{5}}[/tex]
