Answer:
[tex]\frac{-5+/-\sqrt{42} }{8}[/tex]
Step-by-step explanation:
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]. Here a=4, b=5, and c=-1.
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-5+/-\sqrt{5^2-4(4)(-1)} }{2(4)}=\frac{-5+/-\sqrt{25+17} }{8)}[/tex]
[tex]\frac{-5+/-\sqrt{42} }{8}[/tex]
