Respuesta :

WojtekR

[tex]\dfrac{3x+2}{5}-\dfrac{5x-7}{2}=\dfrac{-8x+3}{25}\quad\Big|\cdot 50\\\\\\\\\dfrac{50\cdot(3x+2)}{5}-\dfrac{50\cdot(5x-7)}{2}=\dfrac{50\cdot(-8x+3)}{25}\\\\\\\\10\cdot(3x+2)-25\cdot(5x-7)=2\cdot(-8x+3)\\\\30x+20-125x+175=-16x+6\\\\30x-125x+16x=6-20-175\\\\-79x=-189\quad|:(-79)\\\\\\\boxed{x=\frac{189}{79}=2\frac{31}{79}}[/tex]

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