Answer:
[tex]\large\boxed{x<36}[/tex]
Step-by-step explanation:
[tex]-\dfrac{1}{3}x>-12\qquad\text{change the signs}\\\\\dfrac{1}{3}x<12\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}x<3\cdot12\\\\x<36[/tex]
