Answer:
[tex]\large\boxed{m\angle B\approx60.3^o}[/tex]
Step-by-step explanation:
Use tangent:
[tex]tangent=\dfrac{opposite}{adjacent}[/tex]
We have
[tex]opposite=14\\adjacent=8[/tex]
Substitute:
[tex]\tan B=\dfrac{14}{8}\\\\\tan B=\dfrac{7}{4}\\\\\tan B=1.75\to B\approx60.3^o[/tex]
