Answer:
[tex]\frac{\sqrt{17} }{7}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1, then
sinx = [tex]\sqrt{1-cos^2x}[/tex]
Note that ([tex]\frac{4\sqrt{2} }{7}[/tex])² = [tex]\frac{32}{49}[/tex]
sinΘ = [tex]\sqrt{1-(32/49)}[/tex]
= [tex]\sqrt{\frac{17}{49} }[/tex] = [tex]\frac{\sqrt{17} }{7}[/tex]
