ANSWER
A.
[tex] {f}^{ - 1} (x) = 4x - 3[/tex]
EXPLANATION
Given
[tex]f(x) = \frac{x + 3}{4} [/tex]
Let
[tex]y= \frac{x + 3}{4} [/tex]
Interchange x and y
[tex]x= \frac{y + 3}{4} [/tex]
Solve for y,
[tex]4x = y + 3[/tex]
y=4x-3
This implies that,
[tex] {f}^{ - 1} (x) = 4x - 3[/tex]
