Respuesta :

gmany

Answer:

a. 8 + 12 + 16 + 20; 56

Step-by-step explanation:

[tex]\sum\limits_{k=2}^54k\\\\\text{Make a sum with components equal to 4k,}\\\text{ where k = 2, k = 3, k = 4 and k = 5}:\\\\4(2)=8\\4(3)=12\\4(4)=16\\4(5)=20\\\\8+12+16+20=56[/tex]

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