Answer:
[tex]\large\boxed{x^2-4x-5=(x+1)(x-5)}[/tex]
Step-by-step explanation:
[tex]\text{The factored form:}\\\\ax^2+bx+c=a(x-x_1)(x-x_2)\\\\x_1,\ x_2-the\ zeros\\==============================\\\\\text{We have}\ x^2-4x-5:\\\\x^2-4x-5=x^2+x-5x-5=x(x+1)-5(x+1)\\\\x^2-4x-5=(x+1)(x-5)[/tex]
