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[tex]\displaystyle\\x^2 - 6x + 10 = 0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-40}}{2}=\frac{6\pm\sqrt{-4}}{2}=\frac{6\pm2i}{2}=3\pm~i\\\\ \boxed{\bf~x_1=3-i}\\\boxed{\bf~x_2=3+i}[/tex]

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