Answer:
Option B is correct.
Step-by-step explanation:
[tex]\sqrt[5]{32x^5y^10z^15}[/tex]
We need to solve the above expression.
32 = 2x2x2x2x2 = 2^5
and we know 5√ = 1/5
solving
[tex]=\sqrt[5]{2^5x^5y^{10}z^{15}}\\=(2^5)^{1/5}(5x^5)^{1/5}(y^{10})^{1/5}(z^{15})^{1/5}\\=2xy^2z^3[/tex]
So, simplified form is 2xy^2z^3
So, Option B is correct.
