Answer:
[tex]x^{2}+y^{2}=25[/tex]
Step-by-step explanation:
we know that
The equation of a circle in standard form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center
r is the radius
In this problem we have
(h,k)=(0,0)
r=5 in
substitute
[tex](x-0)^{2}+(y-0)^{2}=5^{2}[/tex]
[tex]x^{2}+y^{2}=25[/tex]
