Respuesta :

padawan
d (xe^y)/dx = d(x - y)dx
(e^y)dx/dx + xd(e^y)/dx = 1 - y'
e^y + xy'e^y = 1 - y'
(1 + xe^y)y' = 1 - e^y
y' = (1 - e^y)/(1 + xe^y)

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