Answer:
x = ± 2
Step-by-step explanation:
Given
f(x) = x² + 1 and (x, 5 ) is a solution then f(x) = 5
Equating the two gives
x² + 1 = 5 ( subtract 1 from both sides )
x² = 4 ( take the square root of both sides )
x = ± [tex]\sqrt{4}[/tex] = ± 2
Thus (- 2, 5) and (2, 5) are solutions
