Answer:
2x - 1
Step-by-step explanation:
Since logarithm has the following property:
If [tex]f(x)=b^x[/tex] and [tex]g(x)=\log_bx[/tex],
Then [tex]fog=b^{\log_bx}=x[/tex] and [tex]gof=\log_bbx=x[/tex]
Therefore,
[tex]- 1 + \ln e^{2x} = - 1 + \log_e e^{2x} = 2x-1[/tex]
