Answer:
The temperature must be 337.42 K.
Explanation:
At constant pressure and number of moles, using Charles's law
[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]
Given ,
At STP,
T₁ = 273.15 K
V₁ = 1700 mL
V₂ = 2100 mL
T₂ = ?
Using above equation as:
[tex]\frac{1700}{273.15}=\frac{2100}{T_2}[/tex]
[tex]T_2=\frac{2100\cdot \:273.15}{1700}\ K[/tex]
The temperature must be 337.42 K.
