the equation of the line has form
y=kx+b
[tex]\left \{ {{5=k*0+b} \atop {9=k*2+b}} \right. \\b=5\\9=2k+5\\2k=4\\k=2[/tex], so
[tex]y=2x+5[/tex]
The second line is parallel to the first and runs 7 units lower, so b=5
[tex]0=1k+5\\k=-5\\y=-5x+5[/tex]
