Answer:
A, D, E
Step-by-step explanation:
BE is the perpendicular bisector of DF. So E is the midpoint of DF, and ∠DEB = 90°. Therefore, A and E are true.
Since DE = EF, and EB = EB, and ΔDEB and ΔFEB are right triangles, they are congruent by SAS. Therefore, BD = BF, so D is true.
