laurenhill3623
laurenhill3623 laurenhill3623
  • 11-06-2020
  • Mathematics
contestada

Please help me with this question!!!!!

Please help me with this question class=

Respuesta :

surjithayer10 surjithayer10
  • 11-06-2020

Answer:

7/25

Step-by-step explanation:

θ lies in quadrant ii

so 2θ lies in quadrant iv

csc θ=5/3

sin θ=3/5 (sin θ=1/csc θ)

[cos(α+β)=cosαcosβ-sinαsinβ]

cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ

=1-2 (3/5)²

=1-2(9/25)

=1-18/25

=(25-18)/25

=7/25

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