Answer:
2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide
Explanation:
Phosphoric acid = Formula: H3PO4
Potassium hydroxide = Formula: KOH
H3PO4 + 3KOH = K3PO4 + 3H2O
Ratio 1:3
7.2 mol Potassium hydroxide = Formula: KOH
7.2/3 = 2.4 Mol Phosphoric acid = Formula: H3PO4
