Answer:
10,450
Step-by-step explanation:
21-13=8 and 29-21=8
So this is aritmetic series where a₁ = 13, and r = 8
Sum of the first n terms:
[tex]S_n=\dfrac{a_1+a_n}{2}\cdot n=\dfrac{a_1+a_1+(n-1)r}{2}\cdot n=\dfrac{2a_1+(n-1)r}{2}\cdot n\\\\\\S_{50}=\dfrac{2\cdot13+(50-1)\cdot8}{2}\cdot50=(13+49\cdot4)\cdot 50=10,450[/tex]
