Answer:
answer C
Step-by-step explanation:
hello,
[tex]x^4-13x^2+36=(x^2-4)(x^2-9)[/tex]
as the sum of the zeroes are 13 and their product 36
4 + 9 = 13
4 * 9 = 36
and then we can write
[tex](x^2-4)=(x-2)(x+2)\\(x^2-9)=(x-3)(x+3)[/tex]
so
[tex]x^4-13x^2+36=(x^2-4)(x^2-9) = (x-2)(x+2)(x-3)(x+3)[/tex]
hope this helps
