Answer:
-(33+110z)/10z
Step-by-step explanation:
(-7/2z +4)+(1/5z -15)
from BODMAS, solving the one in the bracket
First(-7/2z +4)+(1/5z -15)
Find the Lcm
[-7/2z +4] +[1/5z -15]
(7+8z)/2z +(1-75z)/5z
find the Lcm which is 10z
[5(-7+8z) + 2(1-75z)]/10z
[(-35+40z)+(2-150z)]10z
(-35+2+40z-150z)/10z
(-33-110z)/10z
-(33+110z)/10z
