Respuesta :

Willchemistry
Molar mass methanol

CH3OH = 12 + 1 x 3 + 16 + 1 => 32.0 g/mol

32.0 g ----------------- 6.02x10²³ molecules
?? g ------------------ 9.54x10²⁴ molecules

( 9.54x10²⁴) x 32.0 / 6.02x10²³ =

3.0528x10²⁶ / 6.02x10²³ => 507.10 g of methanol

hope this helps!


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