asvsiapno
asvsiapno
13-10-2020
Mathematics
contestada
(6y-7)(3y+1) = 18^y+27y+7y?
Respuesta :
kleenn15
kleenn15
13-10-2020
Answer:
18y²-15y-7
Step-by-step explanation:
6y×3y-7×3y+6y×1-7×1
=18y²-21y+6y-7
=18y²-15y-7
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