Answer:
[tex]\huge\boxed{x=4}[/tex]
Step-by-step explanation:
[tex](3x+8)+(2x+4)=32\\\\3x+8+2x+4=32\qquad|\text{combine like terms}\\\\(3x+2x)+(8+4)=32\\\\5x+12=32\qquad|\text{subtract 12 from both sides}\\\\5x+12-12=32-12\\\\5x=20\qquad|\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{20}{5}\\\\x=4[/tex]
