Step-by-step explanation:
Hey there!
Given;
[tex]16 {x}^{2} - 9 = 0[/tex]
[tex]16 {x}^{2} = 9[/tex]
[tex] {x}^{2} = ± \frac{9}{16} [/tex]
[tex]x = ± \sqrt{ \frac{9}{16} } [/tex]
[tex]x =± \sqrt{ \frac{ {3}^{2} }{ {4}^{2} } } [/tex]
[tex]x = ± \frac{3}{4} [/tex]
Therefore, X= ±3/4.
Hope it helps..
