BlueJayySpazzin BlueJayySpazzin
  • 12-11-2020
  • Mathematics
contestada

CD is parallel to FG and mZFED=126° and mZFCE=42º.
Find: a) mzAFG
b) m BEC
c) mcGFE
d) mzCFE

CD is parallel to FG and mZFED126 and mZFCE42º Find a mzAFG b m BEC c mcGFE d mzCFE class=

Respuesta :

Аноним Аноним
  • 12-11-2020

Step-by-step explanation:

a) 126°

b) 126°

c) 180-126 = 54°

d) 180-54-42 = 84°

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