14-11-2020
Mathematics

contestada

Solve the equation tanxtan(x – 45°)=0 for 0° < x < 360°.

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nopolca nopolca

15-11-2020

Answer:

\tan \left(\frac{\sin \left(x\right)-\cos \left(x\right)}{\cos \left(x\right)+\sin \left(x\right)}\right)

Step-by-step explanation:

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