Answer:
[tex]\huge\boxed{(x^2-6x+9)-2(x^2-3x+1)=-x^2+7}[/tex]
Step-by-step explanation:
[tex](x^2-6x+9)-2(x^2-3x+1)\qquad|\text{use the distributive property}\\\\=x^2-6x+9+(-2)(x^2)+(-2)(-3x)+(-2)(1)\\\\=x^2-6x+9-2x^2+6x-2\qquad|\text{combine like terms}\\\\=(x^2-2x^2)+(-6x+6x)+(9-2)\\\\=-x^2+7[/tex]
