RachelleTorau RachelleTorau

13-12-2020
Mathematics

contestada

factor are given functions 8a^5- 12a^2 + 28a^2

Respuesta :

gufeliz1965 gufeliz1965

13-12-2020

Factor out 4a^2.

4a^2(2a^3 - 3 + 7)

4a^2(2a^3 + 4)

Factor out 2 in the parentheses.

4a^2[2(a^3 + 4)

8a^2(a^3 + 4)

Done.

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