Answer:
82°
Step-by-step explanation:
[tex] \triangle ABC\sim \triangle PQR... (given) [/tex]
[tex] \therefore m \angle Q = m \angle B... (cast) [/tex]
Therefore,
8x + 50 = 3x + 70
8x - 3x = 70 - 50
5x = 20
x = 20/5
x = 4
[tex] m \angle Q [/tex] = 8x + 50 = 8*4 + 50 = 32 + 50 = 82°
