(4x^3 + 2x + 7 ) ÷ (x + 3)
= 4x^3 + 2x + 7 • 1/x+3
= 4x^3 + 2x + 7 / x + 3
Final answer is this:
[tex]\frac{4x^{3}+2x+7}{x+3}[/tex]
