Answer:
[tex]P=0.346atm[/tex]
Explanation:
Hello!
In this case, since the ideal gas equation is:
[tex]PV=nRT[/tex]
And we are asked to compute the pressure, we obtain:
[tex]P=\frac{nRT}{V}[/tex]
Thus, since the temperature must be expressed in Kelvins, we plug in to obtain:
[tex]P=\frac{0.150mol*0.08206\frac{atm*L}{mol*K}*250.15K}{8.90L}\\\\P=0.346atm[/tex]
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