emily2480285
emily2480285 emily2480285
  • 25-02-2021
  • Mathematics
contestada

Find the missing lengths please help for a grade

Find the missing lengths please help for a grade class=

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muhammad655
muhammad655 muhammad655
  • 25-02-2021

Answer:

The answer is

[tex]x = 10 \sqrt{3} \\ y = 5 \sqrt{3} [/tex]

Step-by-step explanation:

[tex] \sin(60) = \frac{15}{x} \\ x= \frac{15}{ \sin(60) } = 10 \sqrt{3} \\ \sin(30) = \frac{y}{10 \sqrt{3} } \\ y = 10 \sqrt{3} \sin(30) \\ y = 10 \sqrt{3} \times .5 \\ y = 5 \sqrt{3} [/tex]

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