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11-03-2021
Chemistry

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A gas occupies 900.0 mL at a temperature of 300K. What is the volume at 132.0 °C?

Respuesta :

11-03-2021

V1/T1=V2/T2
V2=(V1)(T2)/T1
Plug in values given (for the temp you can either turn 300K to 27°C or turn 132°C into kelvin
V2= 4400 mL= 4.4L

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