Answer:
[H+]=1.43*10^-13
pH=12.84
Explanation:
Take the -log of the [OH-] to get the pOH:
pOH= -log(6.98*10^-2)=1.15
pH=14-pOH
pH=14-1.15
pH=12.843
[H+]=10^(-pH)
[H+]=10^(-12.843)
[H+]-1.43*10^-13
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