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Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid carbon. Please hurry!!
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Use the equations below to calculate the enthalpy of formation for propane gas C3H8 from its elements hydrogen gas and solid carbon Please hurry class=

Respuesta :

churst28

Answer: I got -4542.9kg/mol

Explanation:

fichoh

Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol

  • [tex] △H_{f} = Product [/tex]

Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :

  • Product = [tex] 3CO_{2} + 4H_{2}0[/tex]

  • Product = 3(-393.5) + 4(-285.8) = - 2323.70

  • Reactant = [tex] C_{3}H_{8} + 5H_{2}0[/tex]

  • Water, H20 has △H = 0

  • Reactant = [tex] C_{3}H_{8} + 0[/tex]

Enthalpy of formation = product - Reactant

2219.2 = -2323.70 - (propane + 0)

2219.2 = - 2323.70 - propane

Propane = - 2323.70 - 2219.2

[tex] C_{3}H_{8} = - 4542.9 [/tex]

Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.

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