danny121243
danny121243 danny121243
  • 14-05-2021
  • Mathematics
contestada


If y varies inversely as the square ofx, and y = 1/8 when x = 1, find y when x = 5

Respuesta :

ayfat23
ayfat23 ayfat23
  • 19-05-2021

Answer:

25/8

Step-by-step explanation:

The question can be interpreted as

Y= k/x^2.......eqn(1)

Where k= constant if proportionality

y = 1/8 when x = 1,

Substitute, we have

1/8= k/(1)^2

1/8= 1/k

Cross multiply

K= 1/8

find y when x = 5

From eqn(1)

Y= k/x^2

Y= (1/8)/(5)^2

Y=1/8 ×25

Y= 25/8

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