Respuesta :

msm555

Answer:

solution given :

centre (h,k)=(3,-2)

another point (a,b)=(4,-6)

now

radius =[tex] \sqrt{(3-4)²+(-2+6)²} [/tex]=√17

We have

equation of a circle is:

(x-h)²+(y-k)²=r²

(x-4)²+(y+6)²=17 is a required equation.

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