jlesposito2019 jlesposito2019

15-05-2021
Mathematics

contestada

Find the derivative of y=2x^2-3x+1 and the slope of the curve at the point where x=3

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LammettHash LammettHash

16-05-2021

The slope of the tangent line to y(x) at any given x is equal to the derivative dy/dx at that point. Differentiate to get

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\boxed{4x-3}[/tex]

and evaluate it at x = 3 to get the slope, 4•3 - 3 = 9.

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