Answer:
[tex]48.18^{\circ}[/tex]
Step-by-step explanation:
Given that,
Base = 6
Hypotenuse = 9
We need to find the value of [tex]\theta[/tex].
We can use trigonometry to find it such that,
[tex]\cos\theta=\dfrac{B}{H}\\\\\theta=\cos^{-1}(\dfrac{B}{H})\\\\\theta=\cos^{-1}(\dfrac{6}{9})\\\\\theta=48.18^{\circ}[/tex]
So, the value of [tex]\theta=48.18^{\circ}[/tex].
