Answer:
(x + 2)(3x + 2)
Step-by-step explanation:
3x^2 + 8x +4
using middle term break method
so we need two numbers that gives 12 when multiplied and 8 when added.
6 and 2 are the numbers becoz 6*2 =12 and 6+2 =8
3x^2 + (6+2)x +4
multiply the brackets
3x^2 + 6x +2x 4
take commmon
3x(x + 2) +2(x + 2)
take x+2 as common
(x + 2)(3x*1 + 2*1)
(x + 2)(3x +2)
